Opened 8 years ago
Last modified 7 years ago
#10777 closed Bugs
unordered_map treats operator== on stateful allocators as stateless — at Initial Version
Reported by: | anonymous | Owned by: | Daniel James |
---|---|---|---|
Milestone: | To Be Determined | Component: | unordered |
Version: | Boost 1.56.0 | Severity: | Problem |
Keywords: | Cc: |
Description
Hi,
here is my problem: I have a stateful allocator that has a bunch of stuff inside of it. It can be move-assigned. The problem is that boost::unordered_map does this when you have propagate_on_container_move_assign typedeffed to true_type:
my_alloc a; my_alloc b; a = std::move(b); ASSERT(a == b);
That assert can obviously never be true if my_alloc is stateful, but this sequence of events currently happens in boost::unordered_map.
Here is an allocator that shows the problem:
#pragma once #include <memory> #include <vector> template<typename T> struct plalloc {
typedef T value_type;
plalloc() = default; template<typename U> plalloc(const plalloc<U> &) {} plalloc(const plalloc &) {} plalloc & operator=(const plalloc &) { return *this; } plalloc(plalloc &&) = default; plalloc & operator=(plalloc &&) = default;
typedef std::true_type propagate_on_container_copy_assignment; typedef std::true_type propagate_on_container_move_assignment; typedef std::true_type propagate_on_container_swap;
bool operator==(const plalloc & other) const {
return this == &other;
} bool operator!=(const plalloc & other) const {
return !(*this == other);
}
T * allocate(size_t num_to_allocate) {
if (num_to_allocate != 1) {
return static_cast<T *>(::operator new(sizeof(T) * num_to_allocate));
} else if (available.empty()) {
first allocate 8, then double whenever we run out of memory size_t to_allocate = 8 << memory.size(); available.reserve(to_allocate); std::unique_ptr<value_holder[]> allocated(new value_holder[to_allocate]); value_holder * first_new = allocated.get(); memory.emplace_back(std::move(allocated)); size_t to_return = to_allocate - 1; for (size_t i = 0; i < to_return; ++i) {
available.push_back(std::addressof(first_new[i].value));
} return std::addressof(first_new[to_return].value);
} else {
T * result = available.back(); available.pop_back(); return result;
}
} void deallocate(T * ptr, size_t num_to_free) {
if (num_to_free == 1) {
available.push_back(ptr);
} else {
::operator delete(ptr);
}
}
boilerplate that shouldn't be needed, except libstdc++ doesn't use allocator_traits yet template<typename U> struct rebind {
typedef plalloc<U> other;
}; typedef T * pointer; typedef const T * const_pointer; typedef T & reference; typedef const T & const_reference; template<typename U, typename... Args> void construct(U * object, Args &&... args) {
new (object) U(std::forward<Args>(args)...);
} template<typename U, typename... Args> void construct(const U * object, Args &&... args) = delete; template<typename U> void destroy(U * object) {
object->~U();
}
private:
union value_holder {
value_holder() {} ~value_holder() {} T value;
};
std::vector<std::unique_ptr<value_holder[]>> memory; std::vector<T *> available;
};
And here is a sequence of events with which you can get it:
boost::unordered_map<int, int, std::hash<int>, std::equal_to<int>, plalloc<int>> a = { { 1, 2 } }; boost::unordered_map<int, int, std::hash<int>, std::equal_to<int>, plalloc<int>> b = { { 3, 4 } }; boost::unordered_map<int, int, std::hash<int>, std::equal_to<int>, plalloc<int>> c = { { 5, 6 } }; a = std::move(b); a = c;