id	summary	reporter	owner	description	type	status	milestone	component	version	severity	resolution	keywords	cc
11999	int128_t from cpp_int gives unexpected results when bitshifting	Jordi Vermeulen <J.L.Vermeulen@…>	John Maddock	"The 128-bit signed integer int128_t from cpp_int gives some unexpected results when using the bitshift operator. If I shift the value -1 left by 31 bits, then shift it back right by 32 bits, I get the value -0 instead of -1. I do not encounter this problem with the signed integers of larger size (256, 512, 1024). The code below illustrates the problem. I'm using g++ 5.3.0 on Linux Mint (I can test it with Visual Studio 2015 on Windows 7 later if desired).

To be clear: this only seems to happen when shifting right further than left. If I shift right by 31 they all print -1. It's also not just a bug in the conversion to string: if I multiply by 10, int128_t prints 0, but the rest prints -10.

{{{
#include <iostream>
#include <cstdint>
#include <boost/multiprecision/cpp_int.hpp>

using namespace boost::multiprecision;

int main()
{
    int64_t i0 = -1;
    i0 <<= 31;
    i0 >>= 32;
    std::cout << i0 << std::endl; // prints -1

    int128_t i1 = -1;
    i1 <<= 31;
    i1 >>= 32;
    std::cout << i1 << std::endl; // prints -0

    int256_t i2 = -1;
    i2 <<= 31;
    i2 >>= 32;
    std::cout << i2 << std::endl; // prints -1

    int512_t i3 = -1;
    i3 <<= 31;
    i3 >>= 32;
    std::cout << i3 << std::endl; // prints -1

    int1024_t i4 = -1;
    i4 <<= 31;
    i4 >>= 32;
    std::cout << i4 << std::endl; // prints -1

    return 0;
}
}}}
"	Bugs	closed	To Be Determined	multiprecision	Boost 1.60.0	Problem	fixed