https://svn.boost.org/trac10/ticket/696 <pre class="wiki">I'm trying to create an expression that replaces the \p {IsBasicLatin}, that is [\x00-\x7F]. I manage to do it with PERL syntax, but not with 'extended' or 'awk'. It simply doesn't find what I want it to find. The expressions I've tried are: [\\x00-\\x7F] [\\x{00}-\\x{7F}] [[.NUL.]-[.DEL.]] I don't understand the problem, or how I can make it work. Thanks, Moddy. </pre> en-us /htdocs/site/boost.png https://svn.boost.org/trac10/ticket/696 Trac 1.4.3 John Maddock Sun, 30 Jul 2006 16:01:16 GMT https://svn.boost.org/trac10/ticket/696#comment:1 https://svn.boost.org/trac10/ticket/696#comment:1 <ul> <li><strong>status</strong> <span class="trac-field-old">assigned</span> → <span class="trac-field-new">closed</span> </li> </ul> <pre class="wiki">Logged In: YES user_id=14804 In the docs for POSIX regular expressions here: file:///c:/data/boost/develop/boost/libs/regex/doc/syntax_extended.html It says: Character ranges: For example [a-c] will match any single character in the range 'a' to 'c'. By default, for POSIX-Extended regular expressions, a character x is within the range y to z, if it collates within that range; THIS RESULTS IN LOCAL SPECIFIC BEHAVIOUR . This behavior can be turned off by unsetting the collate option flag - in which case whether a character appears within a range is determined by comparing the code points of the characters only. So use boost::regex::extended &amp; ~boost::regex::collate as the syntax type to force character ranges to be independent of the locale. HTH, John. </pre> Ticket