id summary reporter owner description type status milestone component version severity resolution keywords cc 8676 Order of transformed and sliced makes difference j.reid@… Neil Groves "See issue reported here: [http://comments.gmane.org/gmane.comp.lib.boost.devel/242170] Suppose you wish to transform and slice a random access range. Surprisingly the order in which you apply the operations makes a big difference to performance. I'm guessing this is not desired behaviour, correct me if I'm wrong. AFAICT when transforming happens before slicing the iterators involved in the internals of boost.range are being treated as forward iterators not random access iterators. An advance() operation is made on one of the iterators with a negative number and this advance is O(n) for forward iterators but O(1) for random access. The code below demonstrates (adapted from sliced example code). On an unrelated note the documentation for transformed does not mention that the function is part of the range return type. It is given as: boost::transformed_range Code to demonstrate the transform then slice problem: {{{ #include #include #include #include #include #include #include #include struct identity { typedef int result_type; result_type operator()( int i ) const { return i; } }; int main(int argc, const char* argv[]) { using namespace boost::adaptors; using namespace boost::assign; std::vector< int > input; input += 1,2,3,4,5,6,7,8,9; // slicing then transforming my iterator range std::cout << ""Sliced then transformed: ""; boost::copy( input | sliced( 2, 8 ) | transformed( identity() ), std::ostream_iterator< int >( std::cout, "","") ); std::cout << ""\n""; // transforming then slicing my iterator range - takes a very long time.... std::cout << ""Transformed then sliced: ""; boost::copy( input | transformed( identity() ) | sliced( 2, 8 ), std::ostream_iterator< int >(std::cout, "","")); std::cout << ""\n""; return 0; } }}} " Bugs closed To Be Determined range Boost 1.53.0 Problem fixed