Perl regex replacement

[jcombe@…]

I have code that reads a lookup table from memory and then attempts to search for the word found in the lookup table in some data using a regular expression:-

(.*\b)word(\b.*)

Where this matches I call replace with the following

$1WORD$2

This falls down when the word is "2lt" as I get the following to search for

(.*\b)2lt(\b.*)

With replacement

$12LT$2

What happens is it sees $12 as the substring to replace and since I only have two pairs of brackets in my regular expression $12 does not exist and so in effect the 2 in my input data is lost.

I am using Perl format regular expressions (boost::regex::perl)

In Perl I can resolve this by making the replacement

${1}2LT${2}

When I do this using boost I get the literal text as above output (including ${1} etc.) not the text that I expect. Since I've told Boost to use Perl syntax I would expect a regular expression replacement in Perl and Boost to behave the same way.

Is this a bug ?

Thanks Jon

[John Maddock]

Looks like a bug, or at least a missing feature.

Will fix.

John Maddock.

[John Maddock]

(In [50370]) Fix gcc warnings from ICU wrappers. Add optional support for marked sub-expression location information. Add support for ${n} in format replacement text. Fixes #2556. Fixes #2269. Fixes #2514.