Error in boost_typetraits std::min example?

[evan.teran@…]

In the documentation for boost_typetraits, an example is given on how to improve std::min. However, at least at first glance it looks like there is a typo. The example reads:

template <class T, class U>
typename common_type<T, U>::type min(T t, T u)
{
   return t < u ? t : u;
}

Notice that type T is being used for the argument u. If I understand the example better, the point is that the return type of min will be the correct type. But I would expect the u parameter to still have the type U not T.

As it is, I believe that this code will cast the second parameter to type T when it is passed to the function.

[Steven Watanabe]

As this stands, you couldn't call min(x, y) because U can't be deduced.

[John Maddock]

It's a typo, fixed in develop, thanks!